Posted by **rosan** on Friday, November 8, 2013 at 6:40pm.

Four charges are arranged at the corners of a regular tetrahedron (a pyramid with four sides that are identical equilateral triangles). The charges are 1 Coulomb each, and the sides of the tetrahedron are all 1 meter. How much energy in Joules is required to assemble this arrangement of charge

- Physics pls anyone can help me? its urgent -
**bobpursley**, Friday, November 8, 2013 at 9:44pm
Simple. What is the Potential energy of each charge? Well, PE is a scalar, so the distances are the same to each charge, so

energy=k(q1Q2/r+Q1Q3/r+Q1Q4/r+Q2Q3/r+Q2Q4/r+Q3Q4/r)= 6k if all q are 1, all r is 1.

Now consider putting the thing together.

first charge, no energy

second charge, energy= kQq/r=k

third charge, energy= 2k

fourth charge, energy=3k

total work: 6k

- Physics pls anyone can help me? its urgent -
**ss0**, Monday, November 11, 2013 at 10:00am
what is k?

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