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November 24, 2014

November 24, 2014

Posted by **Crystal** on Thursday, November 7, 2013 at 9:46pm.

a) the ball's projection speed and angle

b)the ball's horizontal speed at .5 s into its flight

c) The ball's vertical speed at .5 s into its flight

d) the ball's height at its apex

e) the ball's flight time

f)the ball's flight distance

- Physics -
**Henry**, Saturday, November 9, 2013 at 6:04pmXo = 6 m/s.

Yo = 3.5 m/s.

a. tanA = Yo/Xo = 3.5/6 = 0.58333

A = 30.3o

Vo=Xo/cosA = 6/cos30.3 = 6.95m/s[30.3o]

b. X = Xo = 6 m/s. It does not change.

c. Y = Yo + g*t

Y = 3.5 - 9.8*0.5 = -1.4 m/s. The negative sign means the ball is falling.

d. h=(Y^2-Yo^2)/2g=(0-3.5^2)/-19.6 = 0.625 m.

e. Y = Yo + g*t = 0 @ max. ht.

Tr = (V-Vo)/g = (0-3.5)/-9.8=0.357 s =

Rise time.

Tf = Tr = 0.357 s. = Fall time.

T = Tr + Tf = 0.357 + 0.367 = 0.714 s.

f. D = Xo * t = 6m/s * 0.714s = 4.29 m.

= 0.357 = 0.714 s.

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