Posted by **angela** on Thursday, November 7, 2013 at 9:03pm.

Assume that women's heights are normally distributed with a mean given by u=64.6 in

and a standard deviation given by 0=2.8in.

a) If 1 woman is randomly selected, find the probability that her height is less than 65in.

b) If 49 women are randomly selected, find the probability that they have a mean height less than 65 in.

- statistics -
**Reiny**, Thursday, November 7, 2013 at 9:43pm
great webpage for your problem, just plug in the values that you have

http://davidmlane.com/hyperstat/z_table.html

- statistics -
**Kuai**, Thursday, November 7, 2013 at 10:42pm
a.

z = (65-64.6)/(2.8/sqrt(1))

z = 0.14

b.

z = (65-64.6)/(2.8/sqrt(49))

z = 1

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