Posted by **Raman** on Thursday, November 7, 2013 at 7:46pm.

Janella has only quarters dimes and pennies in her pocket thee are eight coins in all and their total value is 83 cents how many of each type of coins does Janella have?

- Algebra 1 -
**Reiny**, Thursday, November 7, 2013 at 9:14pm
number of quarters= x

number of dimes = y

number of pennies =8-x-y

value:

25x + 10y + 1(8-x-y) = 83

24x+ 9y = 75

9y = 75 - 24x

3y = 25 - 8x

25 -8x must be a positive multiple of 3

so clearly x can only be 1 , 2, or 3

of those only x = 2 will work

if x = 2

3y = 25-16 = 9

y = 3

number of quarter = 2

number of dimes = 3

number of pennies = 8-2-3 = 3

check: does she have 8 coins ? YES

what is the value of those 8 coins?

2(25) + 3(1) + 3(1) = 83 , YEAHHHH

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