math
posted by joemarie on .
a wire 36 meter long is cut into two pieces. each piece is bent to form a rectangle which is 1 cm longer than its width. How long should each piece be to minimize the sum of the areas of the two rectangle?

width of each rectangle = x
length of each rectangle = x+1
sum of area = 2x(x+1) = 2x^2 + 2x
d(area)/dx = 4x + 2
= 0 for a max/min
4x + 2 = 0
4x = 2
x = 1/2
also 2(2x + 2(x+1)) = 36
4x + 4x + 4 = 36
8x=32
x=4
Question makes no sense, check your typing or the wording of the question.