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Show that if A, B, and C are the angles of an acute triangle, then tan A + tan B + tan C = tan A tan B tan C.
I tried drawing perpendiculars and stuff but it doesn't seem to work?
For me, the trig identities don't seem to plug in as well.
Help is appreciated, thanks.

  • Math-Trigonometry -

    C = 180-(A+B), so
    tan C = -tan(A+B) = (tanA+tanB)/(tanAtanB-1)

    = tanA+tanB + (tanA+tanB)/(tanAtanB-1)
    = (tanA+tanB)(1 + 1/(tanAtanB-1))
    = (tanA+tanB)(tanAtanB)/(tanAtanB-1)
    = (tanAtanB)(tanA+tanB)/(tanAtanB-1)
    = tanAtanBtanC

  • Math-Trigonometry -

    Thanks a ton!

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