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January 30, 2015

January 30, 2015

Posted by **Sam** on Wednesday, November 6, 2013 at 5:21pm.

I tried drawing perpendiculars and stuff but it doesn't seem to work?

For me, the trig identities don't seem to plug in as well.

Help is appreciated, thanks.

- Math-Trigonometry -
**Steve**, Wednesday, November 6, 2013 at 7:27pmC = 180-(A+B), so

tan C = -tan(A+B) = (tanA+tanB)/(tanAtanB-1)

tanA+tanB+tanC

= tanA+tanB + (tanA+tanB)/(tanAtanB-1)

= (tanA+tanB)(1 + 1/(tanAtanB-1))

= (tanA+tanB)(tanAtanB)/(tanAtanB-1)

= (tanAtanB)(tanA+tanB)/(tanAtanB-1)

= tanAtanBtanC

- Math-Trigonometry -
**Sam**, Thursday, November 7, 2013 at 10:09amThanks a ton!

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