Posted by **Sam** on Wednesday, November 6, 2013 at 5:21pm.

Show that if A, B, and C are the angles of an acute triangle, then tan A + tan B + tan C = tan A tan B tan C.

I tried drawing perpendiculars and stuff but it doesn't seem to work?

For me, the trig identities don't seem to plug in as well.

Help is appreciated, thanks.

## Answer this Question

## Related Questions

- Trigonometry - Find the exact value of tan(a-b) sin a = 4/5, -3pi/2<a<-pi...
- Trig. - sec^2xcotx-cotx=tanx (1/cos)^2 times (1/tan)-(1/tan)=tan (1/cos^2) times...
- Trig - tan 15° using composite argument? - tan 15° tan (45°-30°) (tan 45° - tan ...
- calculus - can anyone tell me if tan-1x= 1 over tan x? No. They are different. ...
- Trigonometry - Hello, everyone: I am working on finding the exact values of ...
- Integration - Intergrate ¡ì sec^3(x) dx could anybody please check this answer. ...
- trig - h t t p : / / i m g 4 0 . i m a g e s h a c k . u s / c o n t e n t . p h...
- calculus - If limit as delta x approaches 0 of tan(0+Δx)-tan(0)/Δx =1 ...
- precalculus - For each of the following determine whether or not it is an ...
- Math- Precalculus - Write the expression as the sine, cosine, tangent of an ...

More Related Questions