Posted by Jen on Wednesday, November 6, 2013 at 12:19am.
So I need to solve this differential equation
dy/dx = 1/(x+2)
so i solved it like this
dy = 1/(x+2)dx
then i took the integral of both sides
y= ⌠1/(x+2)dx
⌡
then performed a u sub
u = x+2
du = 1dx
y = ⌠du/u
⌡
y = ln abs(u)+c
y = ln abs(x+2)+c
but the sanswer is supposed to be
y = ln abs ((x+2)/2) + c
Where did I mess up? and where did the 2 in the denominatior of the (x+2) come from?

math  Steve, Wednesday, November 6, 2013 at 12:27am
Not sure where the 2 came from, but since
ln(u/2) = ln(u)  ln(2)
just fold the ln(2) into the C.

math  Jen, Wednesday, November 6, 2013 at 12:43am
okay thank you!

math  amar, Wednesday, November 6, 2013 at 1:20am
i don't know answer.i am tring to find answer
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