# math

posted by
**Jen**
.

So I need to solve this differential equation

dy/dx = 1/(x+2)

so i solved it like this

dy = 1/(x+2)dx

then i took the integral of both sides

y= ⌠1/(x+2)dx

⌡

then performed a u sub

u = x+2

du = 1dx

y = ⌠du/u

⌡

y = ln abs(u)+c

y = ln abs(x+2)+c

but the sanswer is supposed to be

y = ln abs ((x+2)/2) + c

Where did I mess up? and where did the 2 in the denominatior of the (x+2) come from?