How many moles of Aluminium Bromide is fromed from 4.0 moles of Aluminium in equation: 2Al + 3 Br2 = 2 AlBr3?
please explain
In the balanced chemical equation 2Al + 3Br2 → 2AlBr3, it is stated that 2 moles of aluminum react with 3 moles of bromine gas to form 2 moles of aluminum bromide.
Given that we have 4.0 moles of aluminum, we can use the stoichiometric ratio to calculate how many moles of aluminum bromide are formed.
(4.0 moles Al) x (2 moles AlBr3 / 2 moles Al) = 4.0 moles AlBr3
Therefore, 4.0 moles of aluminum bromide are formed from 4.0 moles of aluminum.
To determine the number of moles of aluminum bromide (AlBr3) formed from 4.0 moles of aluminum (Al), we need to use the stoichiometric coefficients in the balanced chemical equation.
The balanced chemical equation for the reaction is:
2 Al + 3 Br2 = 2 AlBr3
From the equation, we can see that 2 moles of aluminum react to form 2 moles of aluminum bromide. Therefore, if we have 4.0 moles of aluminum (Al), we can expect to form 4.0 moles of aluminum bromide (AlBr3) because the mole ratio is 1:1.
Hence, 4.0 moles of aluminum will form 4.0 moles of aluminum bromide.
Use the coefficients to convert anything you have in the equation to anything you want in the equation.
mols AlBr3 = 4.0 mol Al x (2 mols AlBr3/2 mol Al) = 4.0 x 2/2 = 4.0 x 1 = 4.0 mols AlBr3 formed.