A hardworking ant must supply 0.00955 N to pull a small piece of fruit at constant velocity over a distance of 8.60 cm up a small hill to the entrance of the colony. If the coefficient of kinetic friction between the piece of fruit and the 16.2° sloped hill is 0.540, calculate the work done by the ant by pulling the piece of fruit up the hill.

what is

.00955*.0860? force*distance

To calculate the work done by the ant, we need to first determine the force applied by the ant to overcome the friction and pull the piece of fruit up the hill.

The force required to overcome friction can be calculated using the equation:

force of friction = coefficient of kinetic friction * normal force

The normal force is the force exerted by the hill on the piece of fruit perpendicular to the surface. In this case, it is the component of the weight of the fruit perpendicular to the hill, which can be found using the equation:

normal force = weight * cos(theta)

where theta is the angle of the hill (16.2°) and weight is the force of gravity acting on the fruit. Weight can be calculated using the equation:

weight = mass * acceleration due to gravity

Now, we have all the information needed to calculate the force of friction. Rearranging the equation for force of friction:

force of friction = coefficient of kinetic friction * normal force

We can calculate the force of friction using the given coefficient of kinetic friction and the normal force calculated previously.

Next, we can determine the work done by the ant using the equation:

work done = force * distance

where force is the force applied by the ant to pull the fruit and distance is the displacement of the fruit up the hill.

Plugging in the calculated force of friction and the given distance into the equation, we can find the work done by the ant.