Na3PO4(aq) and AgNO3(aq). Write the ionic equation.

silver phosphate forms a precipitate.

PO4-3 + 3Ag+ >>Ag3PO4 (s)

To write the ionic equation for the reaction between Na3PO4(aq) and AgNO3(aq), we need to first write the balanced molecular equation and then break it down into its ionic components.

Step 1: Write the balanced molecular equation:
Na3PO4(aq) + 3AgNO3(aq) -> Ag3PO4(s) + 3NaNO3(aq)

Step 2: Split the soluble compounds into its respective ions:
Na3PO4(aq) breaks down into 3Na+(aq) + PO4^3-(aq)
AgNO3(aq) breaks down into Ag+(aq) + NO3-(aq)

Step 3: Write the ionic equation by replacing the soluble compounds with their respective ions:
3Na+(aq) + PO4^3-(aq) + 3Ag+(aq) + 3NO3-(aq) -> Ag3PO4(s) + 3Na+(aq) + 3NO3-(aq)

Step 4: Simplify the equation by removing the spectator ions, which are ions that appear on both sides of the equation:
3Na+(aq) + PO4^3-(aq) + 3Ag+(aq) -> Ag3PO4(s)

Therefore, the ionic equation for the reaction between Na3PO4(aq) and AgNO3(aq) is:
3Na+(aq) + PO4^3-(aq) + 3Ag+(aq) -> Ag3PO4(s)

To write the ionic equation for the reaction between Na3PO4(aq) and AgNO3(aq), we need to first determine the products of the reaction by swapping the cations and anions.

The cation in Na3PO4 is Na+ (sodium ion), and the cation in AgNO3 is Ag+ (silver ion).
The anion in Na3PO4 is PO4^3- (phosphate ion), and the anion in AgNO3 is NO3^- (nitrate ion).

Therefore, the products of the reaction are Ag3PO4 (silver phosphate) and NaNO3 (sodium nitrate).

Now, let's write the molecular equation:

Na3PO4(aq) + 3AgNO3(aq) → 3NaNO3(aq) + Ag3PO4(s)

To write the ionic equation, we need to split all the soluble ionic compounds into their respective ions:

Na3PO4(aq): 3Na+ (aq) + PO4^3- (aq)
AgNO3(aq): Ag+ (aq) + NO3^- (aq)
NaNO3(aq): Na+ (aq) + NO3^- (aq)
Ag3PO4(s): Ag3PO4 (s)

Now, let's write the ionic equation by removing the spectator ions (ions that appear on both sides of the equation):

3Ag+ (aq) + PO4^3- (aq) → Ag3PO4 (s)

Therefore, the ionic equation for the reaction between Na3PO4(aq) and AgNO3(aq) is:

3Ag+ (aq) + PO4^3- (aq) → Ag3PO4 (s)