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March 27, 2015

March 27, 2015

Posted by **tee** on Monday, November 4, 2013 at 1:20am.

- math -
**Bosnian**, Monday, November 4, 2013 at 3:06ama = the length of the shortest side

b = the length of the middle side

c = the length of the longest side

P = the perimeter

The perimeter of a triangle is 42 inches.

P = a + b + c

a + b + c = 42 Subtract c to both sides

a + b + c - c = 42 - c

a + b = 42 - c

The sum of the length of the longest side and twice the sum of both the other side lengths is 65 inches.

c + 2 ( a + b ) = 65

c + 2 ( 42 - c ) = 65

c + 2 * 42 - 2 * c = 65

c + 84 - 2 c = 65

- c + 84 = 65 Add c to both sides

- c + 84 + c = 65 + c

84 = 65 + c Subtract 65 to both sides

84 - 65 = 65 + c - c

19 = c

c = 19 in

Three times the length of the longest side minus the length of the shortest side is 49 inches.

3 c - a = 49 Add a to both sides

3 c - a + a = 49 + a

3 c = 49 + a Subtract 49 to both sides

3 c - 49 = 49 + a - 49

3 c - 49 = a

a = 3 c - 49

a = 3 * 19 - 49

a = 57 - 49 = 8

a = 8 in

a + b + c = 42

8 + b + 19 = 42

27 + b = 42 Subtract 27 to both sides

27 + b - 27 = 42 - 27

b = 15 in

The side lengths:

a = 8 in

b = 15 in

c = 19 in

- math -
**Bosnian**, Monday, November 4, 2013 at 3:08am84 = 65 + c Subtract 65 to both sides

84 - 65 = 65 + c - 65

19 = c

c = 19 in

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