Posted by **Kimmy** on Sunday, November 3, 2013 at 8:24pm.

A uniform rod of mass M = 437.0 g and length L = 37.1 cm stands vertically on a horizontal table. It is released from rest to fall.

A)Which of the following forces are acting on the rod?

B)Calculate the angular speed of the rod as it makes an angle θ = 45° with respect to the vertical.

C)Calculate the vertical acceleration of the moving end of the rod as it makes an angle θ = 45° with respect to the vertical (take upward as positive and downward as negative).

D)Calculate the normal force exerted by the table on the rod as it makes an angle θ = 45° with respect to the vertical.

E) If the rod falls onto the table without slipping, find the linear acceleration of the end point of the rod when it hits the table

## Answer This Question

## Related Questions

- physics - A uniform rod of mass M = 0.245kg and length L = 0.49m stands ...
- Physics - A uniform rod AB of length 2a and mass M is freely pivoted at A and is...
- Physics - A thin uniform rod (length = 1.3 m, mass = 3.2 kg) is pivoted about a ...
- Physics (please help!!!!) - A thin uniform rod (length = 1.3 m, mass = 4.1 kg) ...
- physics - A thin non-uniform rod of length L=2.00 m and mass M=9.00 kg is free ...
- physics - A uniform rod is set up so that it can rotate about a perpendicular ...
- College Physics - A thin rod (uniform density & thickness) has mass M and length...
- physics - A uniform thin rod of length 0.55 m and mass 5.5 kg can rotate in a ...
- AP Physics - A uniform thin rod of length 0.3m and mass 3.5kg can rotate in a ...
- physics - A homogeneous rod AB=100 cm of mass m=4kg is suspended from a fixed ...

More Related Questions