Posted by Mary on .
Consider the reaction shown:
452 kcal + 4 PCl5 (s) ¨ P4 (s) + 10 Cl2(g)
This reaction is ________ because the sign of ƒ¢H is ________.
A) exothermic; neither positive nor negative
B) endothermic; positive
C) endothermic; negative
D) exothermic; positive
E) exothermic; negative
The equation shows heat is added; therefore, the reaction is endothermic so the sign of delta H will be ......?