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March 30, 2015

March 30, 2015

Posted by **Kirsten** on Sunday, November 3, 2013 at 7:03pm.

- algebra -
**Reiny**, Sunday, November 3, 2013 at 8:07pmThey will have traveled the same distance, but the difference is their times will be 2 hours

time for slower train = D/80

time for faster train = D/90

D/80 - D/90 = 2

times 720

9D - 8D = 1440

D = 1440

Time for train B (the faster) = 1440/90 = 16 hrs.

check:

in 16 hrs, the faster train goes 16(90) = 1440

in 18 hrs, the slower train goes 18(80) = 1440

yeahhh!

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