Posted by **Kirsten** on Sunday, November 3, 2013 at 7:03pm.

Train A leaves a station traveling at 80km/h. Two hours later, train B leaves the same direction at 90km/h. How long does it take train B to catch up to train A?

- algebra -
**Reiny**, Sunday, November 3, 2013 at 8:07pm
They will have traveled the same distance, but the difference is their times will be 2 hours

time for slower train = D/80

time for faster train = D/90

D/80 - D/90 = 2

times 720

9D - 8D = 1440

D = 1440

Time for train B (the faster) = 1440/90 = 16 hrs.

check:

in 16 hrs, the faster train goes 16(90) = 1440

in 18 hrs, the slower train goes 18(80) = 1440

yeahhh!

## Answer This Question

## Related Questions

- pre algebra - train A leaves a station at 1:15 PM,traveling 60 mph.Train B ...
- Math - Train A and train B leave station going in opposite directions. Train B ...
- Math - 5) A freight train leaves a station traveling at 32 km/h. Two hours later...
- math - Train leaves a stationa traveling at 60 miles per hour. Eight hours later...
- Mathematics - A train leaves station x and travels east at 30 kph. Two hours ...
- Algebra - Trains A and B are traveling in the same direction on parallel tracks...
- algebra - Trains A and B are traveling in the same direction on parrallel tracks...
- algebra - Trains A and B are traveling in the same direction on parrallel ...
- math - Trains A and B are traveling in the same direction on parrallel tracks. ...
- Algebra - A train leaves the station at 8 a.m. and averages 40 miles per hour ...

More Related Questions