Aluminum metal and hydrogen chloride react to form aluminum chloride and hydrogen gas.

a.)How many moles of aluminum metal are needed to produce 3.33 moles of aluminum chloride?

b.)How many moles of hydrogen chloride are needed to react with this number of moles of aluminum metal?

To determine the number of moles of aluminum metal needed to produce 3.33 moles of aluminum chloride, we need to consider the balanced chemical equation for the reaction:

2Al + 6HCl -> 2AlCl3 + 3H2

According to the balanced equation, 2 moles of aluminum are required to produce 2 moles of aluminum chloride. Therefore:

a.) To find the number of moles of aluminum needed, we can set up a proportion:

2 moles Al : 2 moles AlCl3 = x moles Al : 3.33 moles AlCl3

Simplifying the proportion gives us:

2/2 = x/3.33

x = (2/2) * 3.33 = 3.33 moles

Therefore, 3.33 moles of aluminum metal are needed to produce 3.33 moles of aluminum chloride.

To determine how many moles of hydrogen chloride are needed to react with this number of moles of aluminum metal, we can again use the balanced chemical equation:

2Al + 6HCl -> 2AlCl3 + 3H2

According to the equation, 6 moles of hydrogen chloride are required to react with 2 moles of aluminum. Therefore:

b.) To find the number of moles of hydrogen chloride needed, we can set up another proportion:

6 moles HCl : 2 moles Al = x moles HCl : 3.33 moles Al

Simplifying the proportion gives us:

6/2 = x/3.33

x = (6/2) * 3.33 = 9.99 moles

Therefore, approximately 9.99 moles of hydrogen chloride are needed to react with 3.33 moles of aluminum metal.

To answer these questions, we can use the balanced chemical equation for the reaction between aluminum metal and hydrogen chloride:

2Al + 6HCl -> 2AlCl3 + 3H2

a.) To calculate the moles of aluminum metal needed to produce 3.33 moles of aluminum chloride, we can use the stoichiometry of the balanced equation. According to the equation, 2 moles of aluminum react to produce 2 moles of aluminum chloride. Therefore, the ratio of moles of aluminum to moles of aluminum chloride is 2:2 or 1:1.

So, if we have 3.33 moles of aluminum chloride, we also need 3.33 moles of aluminum metal.

b.) Using the balanced equation, we see that the ratio of moles of hydrogen chloride to moles of aluminum is 6:2 or 3:1.

Therefore, if we have 3.33 moles of aluminum metal, we need (3.33 moles * 3) / 1 = 9.99 moles of hydrogen chloride to react with this amount of aluminum metal.

See your other posts. This is done the same way. Use the coefficients.