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January 29, 2015

January 29, 2015

Posted by **Lisa** on Sunday, November 3, 2013 at 6:35pm.

1. What does this p-value suggest about the effectiveness of the DVD?

A) This is low p-value which leads us to reject the null hypothesis and conclude that the DVD is more effective than sending a letter.

B) This is low p-value which leads us to reject the null hypothesis and we cannot conclude that the DVD is more effective than sending a letter.

C) This is not a low p-value so we fail to reject the null hypothesis and conclude that the DVD is more effective than sending a letter.

D) This is not a low p-value so we reject the null hypothesis and conclude that the DVD is more effective than sending a letter.

E) The p-value is not helpful in making a decision.

2. What additional information might be helpful in making the decision about the effectiveness of the DVD?

A) The results are very clear so no additional information is needed.

B) A confidence interval would be helpful since we can only state that the proportion of delinquent customers who pay after getting the DVD is greater than 30%.

C) The bank statistician should recalculate the p-value since it is probably incorrect.

D) A confidence interval would be helpful since we can only state that the proportion of delinquent customers who pay after getting the DVD is less than 30%.

- Statistics Problems -
**Anonymous**, Sunday, November 3, 2013 at 10:22pmA market sells potatoes whose weights are normally distributed with mean 65 grams and standard deviation 15 grams.

(i) Find the probability that a randomly chosen potato weighs between 40 grams and 80 grams.

The market sells potatoes weighing more than 80 grams separately packaged. Potatoes weighing between 80 grams and L grams are labeled large and potatoes weighing over L grams are labeled as extra-large.

(ii) Given that a randomly chosen potato is twice as likely to be large as extra-large, calculate the value of L. A market sells potatoes whose weights are normally distributed with mean 65 grams and standard deviation 15 grams.

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