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January 30, 2015

January 30, 2015

Posted by **John** on Sunday, November 3, 2013 at 3:46pm.

- Algebra -
**Steve**, Sunday, November 3, 2013 at 8:27pmYou have two cases:

h-7 >=0, where |h-7| = h-7

h-7 < 0, where |h-7| = -(h-7)

So,

case 1: h-7 >= 0 (h >= 7)

-2(h-7) = -28

h-7 = 14

h = 21

Since 21 >= 7, it's a solution

Case 2: h-7 < 0 (h < 7)

-2(-(h-7)) = -28

2h-14 = -28

2h = -14

h = -7

Since -7 < 7, it's a solution

So, h=-7,21

Another way to look at it is to say

-2|h-7| = -28

|h-7| = 14

That means that h has to be at a distance of 14 from 7, either above or below. So, h = -7 or 21

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