Posted by **Robin** on Sunday, November 3, 2013 at 3:44pm.

A) Find the average value of

f(x)=x^3-x+1 on the interval (0,2)

B) Find c so that f(c)equals the average value

- Calculus -
**Steve**, Sunday, November 3, 2013 at 8:38pm
avg value is area divided by width, so

1/2 ∫[0,2] x^3-x+1 dx

= 2

So, since the area is 4, and the width is 2, a rectangle of height 2 will have the same area.

We need to solve

f(x) = 2

x^3-x+1 = 2

x^3-x-1 = 0

x = 1.32

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