Sunday

December 21, 2014

December 21, 2014

Posted by **Robin** on Sunday, November 3, 2013 at 3:44pm.

f(x)=x^3-x+1 on the interval (0,2)

B) Find c so that f(c)equals the average value

- Calculus -
**Steve**, Sunday, November 3, 2013 at 8:38pmavg value is area divided by width, so

1/2 ∫[0,2] x^3-x+1 dx

= 2

So, since the area is 4, and the width is 2, a rectangle of height 2 will have the same area.

We need to solve

f(x) = 2

x^3-x+1 = 2

x^3-x-1 = 0

x = 1.32

**Answer this Question**

**Related Questions**

Calculus - a)Find the average value of f(x) = e-x over the interval [0,k] b)What...

Calculus - I'm supposed to find the average value of the function over the given...

calculus - Find the average value of the function f(x)=8x^2-5x+6 , on the ...

Calculus - Use the Fundamental Theorem of Calculus to find the area of the ...

Calculus Please help! - f(x) -2x^3+2x^2-3x+2 Find the average slope of this ...

Calculus Help!! - Region R is bounded by the functions f(x) = 2(x-4) + pi, g(x...

calculus - Let g(x)=f(2x). Show that the average value of f on the interval [0,...

calculus - Find a value c in the interval [0,2] such that f(c)is equal to the ...

calculus - Let A(x) be the area of the rectangle inscribed under the curve with ...

calculus - Consider the given function and the given interval. f(x) = 4 sin x &#...