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October 1, 2014

October 1, 2014

Posted by **Anonymous** on Sunday, November 3, 2013 at 10:32am.

- calculus -
**Steve**, Sunday, November 3, 2013 at 11:58amIf we assume A is at (0,0) at noon, the the distance z is

z^2 = (150-25t)^2 + (20t)^2

now get z when t=4

and find dz/dt from

2z dz/dt = -50(150-25t) + 40(20t)

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