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At noon, ship A is 150 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is the distance between the ships changing at 4:00 PM?

  • calculus - ,

    If we assume A is at (0,0) at noon, the the distance z is

    z^2 = (150-25t)^2 + (20t)^2
    now get z when t=4
    and find dz/dt from

    2z dz/dt = -50(150-25t) + 40(20t)

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