Charlotte is training for a marathon. Right now she is 21km from home. She is running toward home at a rate of 10 km per hour.(Let x=time(in hours); y=distance from home (in km).) [lHint: Charlottle's distance from home is decreasing.]

There is no question in your post.

Do you want the equation for the distance she is from home?

then

y = -10x + 21 , where x and y are as defined

can u help me put it in a table format

To find out how long it will take for Charlotte to reach home, we can use the formula for speed: speed = distance / time.

In this case, we know Charlotte's speed is 10 km/h, and she is running towards home, so the distance is decreasing. Therefore, we need to calculate the time it will take for Charlotte to go from 21 km to 0 km.

Let's denote x as the time in hours and y as the distance from home in km at a certain time.

Given that Charlotte is running towards home at a rate of 10 km/h, we can create the equation:

y = 21 - 10x

To find the time it will take to reach home (when y = 0), we need to solve for x:

0 = 21 - 10x

To isolate x, we subtract 21 from both sides:

10x = 21

Finally, we divide both sides by 10:

x = 21 / 10

Simplifying further, we can express the time it will take for Charlotte to reach home as:

x = 2.1 hours, or 2 hours and 6 minutes.

Therefore, it will take Charlotte approximately 2 hours and 6 minutes to reach home.