Rain is falling vertically down on a car moving at 11 m/s. Tracks made by the raindrops on the side window of the car are inclined at 55 degrees with the vertical. Find the speed of the raindrop relative to the ground.

To find the speed of the raindrop relative to the ground, we need to consider the velocity of the car and the angle at which the tracks made by the raindrops are inclined.

Let's analyze the situation:
1. The vertical component of the raindrop's velocity relative to the car is due to the rain falling straight down. We can calculate this component by multiplying the speed of the car by the sine of the angle of inclination: v_vertical = 11 m/s * sin(55°).
2. The horizontal component of the raindrop's velocity relative to the car is zero since the rain is falling straight vertically.
3. Since we are interested in the speed of the raindrop relative to the ground, we need to combine the vertical component of the raindrop's velocity relative to the car with the velocity of the car.
a) The velocity of the car is 11 m/s.
b) The vertical component of the raindrop's velocity relative to the car is v_vertical = 11 m/s * sin(55°).
c) The speed of the raindrop relative to the ground is the vector sum of the car's velocity and the vertical component of the raindrop's velocity: speed_relative_to_ground = √(11 m/s)^2 + (11 m/s * sin(55°))^2.

Now, let's calculate the speed of the raindrop relative to the ground:
1. Calculate the vertical component of the raindrop's velocity relative to the car: v_vertical = 11 m/s * sin(55°).
v_vertical ≈ 11 m/s * 0.819 (rounded to three decimal places)
v_vertical ≈ 9.009 m/s (rounded to three decimal places)
2. Calculate the speed of the raindrop relative to the ground: speed_relative_to_ground = √(11 m/s)^2 + (9.009 m/s)^2.
speed_relative_to_ground ≈ √(121 m^2/s^2 + 81.163 m^2/s^2)
speed_relative_to_ground ≈ √202.163 m^2/s^2
speed_relative_to_ground ≈ 14.212 m/s (rounded to three decimal places)

Therefore, the speed of the raindrop relative to the ground is approximately 14.212 m/s.

To find the speed of the raindrop relative to the ground, we need to first break down the velocity of the raindrop into its horizontal and vertical components.

Let's assume the speed of the raindrop relative to the car is v, and the angle between the raindrop's velocity and the vertical is α.

Given:
Speed of the car (v_car) = 11 m/s
Angle of inclination of raindrop tracks with the vertical (α) = 55 degrees

The vertical component of the raindrop's velocity (v_y) can be calculated using trigonometry:
v_y = v * sin(α)

The horizontal component of the raindrop's velocity (v_x) is equal to the velocity of the car (v_car) since the rain is falling vertically down:
v_x = v_car = 11 m/s

Now, we can calculate the speed of the raindrop relative to the ground (v_ground) using the Pythagorean theorem:
v_ground = sqrt(v_x^2 + v_y^2)

Substituting the values we have:
v_ground = sqrt((11 m/s)^2 + (v * sin(55 degrees))^2)

Now, we need to find the value of v. To do that, we need additional information or assume a specific value for v.