Posted by **Anonimus** on Saturday, November 2, 2013 at 6:58am.

A meteorite of mass m= 2 ×104 kg is approaching head-on a planet of mass M= 7 ×1029 kg and radius R= 5 ×104 km. Assume that the meteorite is initially at a very large distance from the planet where it has a speed v0= 5 ×102 km/s. Take G= 6.67 ×10−11.

Determine the speed of the meteorite v (in m/s) just before it hits the surface of the planet. (The planet has no atmosphere, so we can neglect all friction before impact)

v=

- physics(URGENT!!!!!) -
**bobpursley**, Saturday, November 2, 2013 at 9:10am
Intiial PE=GMm/r

Initial KE=1/2 m v^2

can you convert that intial energy to final ke?

- physics(URGENT!!!!!) -
**Anonymous**, Saturday, November 2, 2013 at 9:20am
my final formula is: Vf=sqrt(Vi^2+(mMG/r))

r being the radius of the planet

- physics(URGENT!!!!!) -
**bobpursley**, Saturday, November 2, 2013 at 9:23am
1/2 m vf^2=1/2 m vi^2+GMm/r

where r is the initial distance of the object. You can ignore the final PE, as the object is very far from the planet initiually. That does not lead to what you got.

- physics(URGENT!!!!!) -
**Anonymous**, Saturday, November 2, 2013 at 9:29am
but isn't the object initially at r=infinity therefore P_i=0 and the potential energy just before impact Mmg/the radius of the planet? or am i completely of target

- physics(URGENT!!!!!) -
**Sat**, Sunday, November 3, 2013 at 3:07pm
1/2 m vf^2=1/2 m vi^2+GMm/r - it's correct!

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