Emory tosses a nickle four times. The probability that he gets at least as many heads as tails is? Explain
To find the probability that Emory gets at least as many heads as tails when tossing a nickel four times, we can use the concept of counting favorable outcomes and total outcomes.
Let's observe all the possible outcomes when tossing a nickel four times. Each toss has two possible outcomes: either a head (H) or a tail (T). So, the total number of possible outcomes is 2^4 since there are four tosses.
The next step is to determine the favorable outcomes, which are the outcomes where Emory gets at least as many heads as tails. Let's list all the favorable outcomes:
1. HHHH (4 heads, 0 tails)
2. THHH (3 heads, 1 tail)
3. TTHH (2 heads, 2 tails)
4. TTTH (1 head, 3 tails)
5. TTTT (0 heads, 4 tails)
In this case, there are five favorable outcomes.
To calculate the probability, we divide the number of favorable outcomes by the total number of possible outcomes:
Probability = Favorable Outcomes / Total Outcomes
Probability = 5 / 2^4 = 5 / 16 = 0.3125
Therefore, the probability that Emory gets at least as many heads as tails when tossing a nickel four times is 0.3125 or 31.25%.