The figure shows a person whose weight is W = 500 N doing push-ups. Find the normal force exerted by the floor on (a) each hand and (b) each foot, assuming that the person holds this position.
Well, isn't this person quite the superhero doing push-ups with a weight of 500 N! Let's break it down, shall we?
(a) To determine the normal force exerted by the floor on each hand, we need to consider that the person is holding their weight evenly between two hands. So, we divide the weight by the number of hands. Assuming this person has a regular number of hands (two), the normal force on each hand would be 250 N. But hey, even superheroes need to share the load.
(b) Now, for the normal force exerted on each foot, we must consider that the weight is being distributed between two feet. So, we divide the weight by the number of feet. Assuming this person has a regular number of feet (two again), the normal force on each foot would also be 250 N. It's all about keeping things balanced, just like a circus act!
So, in summary, assuming the person holds the position, the normal force on each hand would be 250 N, and the normal force on each foot would also be 250 N. Looks like equilibrium is the key here, and this person is pulling off some impressive balancing act!
To find the normal force exerted by the floor on the person's hands and feet during a push-up, let's assume the person is doing a standard push-up position with hands and feet on the ground.
(a) To find the normal force exerted by the floor on each hand, we can start by considering the forces acting on the person's hands. The weight of the person provides a downward force of 500 N. According to Newton's third law, the floor exerts an equal and opposite force on each hand. Therefore, the normal force exerted by the floor on each hand is also 500 N.
(b) To find the normal force exerted by the floor on each foot, we consider the forces acting on the person's feet. Again, the weight of the person provides a downward force of 500 N. According to Newton's third law, the floor exerts an equal and opposite force on each foot. Therefore, the normal force exerted by the floor on each foot is also 500 N.
In summary, the normal force exerted by the floor on each hand and each foot during a push-up is 500 N.
To find the normal force exerted by the floor on each hand and each foot, we need to consider the forces acting on the person.
In this case, the gravitational force acting on the person is represented by the weight W = 500 N.
(a) For each hand:
When the person is doing push-ups, we can assume that their body is in equilibrium, meaning the net force acting on the person is zero.
In this position, each hand supports half of the person's weight since the person is symmetrically holding the position. Therefore, the normal force exerted by the floor on each hand is half of the person's weight.
Normal force on each hand = (1/2) * Weight
Normal force on each hand = (1/2) * 500 N
Normal force on each hand = 250 N
(b) For each foot:
Since the person is symmetrically holding the position, each foot also supports half of the person's weight. Thus, the normal force exerted by the floor on each foot is also half of the person's weight.
Normal force on each foot = (1/2) * Weight
Normal force on each foot = (1/2) * 500 N
Normal force on each foot = 250 N
Therefore, the normal force exerted by the floor on each hand is 250 N, and the normal force exerted by the floor on each foot is also 250 N.