Jill has 5 pictures to hang on her wall she wants to hang one picture in the center if the picture remains the same how many diffrent ways can she hang the other pictures
what you typed makes no sense to me did you mean this by leaving out "and the other 4 at the corners of the center picture."
Jill has 5 pictures to hang on her wall. She wants to hang one picture in the center and the other 4 at the corners of the center picture. if the picture in the center remains the same, how many different ways can she hand the other pictures
if so then it would be 4!
4! is the same as
4 times 3 times 2 times 1 = 24 that's your answer
24
How do we draw the 24 ways to put the picture
To find out how many different ways Jill can hang the other pictures, we need to calculate the number of permutations.
In this case, Jill has 4 remaining pictures to hang on the wall because one picture is already hung in the center. The remaining pictures can be arranged in (4!) = 4 x 3 x 2 x 1 = 24 different ways, where "!" represents the factorial function.
Therefore, Jill can hang the other pictures in 24 different ways.