posted by Maryam on .
At t=0, a particle leaves the origin with a velocity 6m/s in the positive x direction and moves in the x-y plane with a constant acceleration (-2i-4j)m/s2
How far the particle from the origin at t=1 ?
displacement=vi*t+1/2 a t^2
= 6i*1+1/2 (-2i-4j)*1
combine terms. Then how far is = sqrt (icomponent^2+jcomponent^2)
The only issue, is x direction the i direction?