Posted by andra on .
1. y= 5x+2
y=3x14
2. x+y=0
5x+y=4
3. 6x+2y=4
4x+2=8

Substution Soluton MATH 
Sam,
1. subtituting we get 5x + 2 = 3x14
so we get 8x = 16 and x=2, then plugging back in we get y = 2*5 + 2 = 8
2. subtracting first from second equation gives us 4x = 4 so x = 1, and y = 1
3. 4x + 2 = 8 so 4x = 6, and x = 3/2
also thus 3/2*6 + 2y = 4
2y= 5
y = 5/2
maybe you had a typo and meant the second equation is 4x+2y = 8
so then we subtract frist equation from second one and get 2x = 2, x=1
then we plug back in for the second one to get 4 + 2y = 8
y= 12/2 = 6
:D 
Substution Soluton MATH 
Reiny,
1. since we have two expressions each equal to y, just equate them:
3x14 = 5x+2
8x = 16
x=2
sub into one of them:
y = 3x14 = 614 = 8
2. from the first : y = x
into the 2nd:
5x x = 4
4x=4
x = 1
then y = 1
3. probably a typo , you meant: 4x + 2y = 8
6x+2y=4
4x+2y=8
subtract them:
2x = 4
x = 2
into 4x+2y=8 > 8+2y=8
2y = 16
y = 8 
Substution Soluton MATH 
andra,
Reiny I don't understand the second part of number 3. Please explain. Actually I really didn't understand the whole thing. Why did you subtract the two equations? than when you got the answer for x I don't even know what happened after that

Substution Soluton MATH 
Reiny,
3. Assuming it was a typo and the 2nd equation was 4x+2y = 8,
notice that both terms contain 2y as the yterm.
The method I used is called "elimination".
if we subtract the two equations, of course we can only add/subtract like terms, I get:
6x4x = 2x
2y  2y = 0 > Ahh, I have "eliminated" the y term
48 = 4
giving me
2x + 0 = 4
2x = 4
x = 2
now go back to either of the original equations, I picked the 2nd
4x+2y = 8
4(2) + 2y = 8
8 + 2y = 8
2y = 16
y = 8
You should try substituting x=2 into the first, to see that you get the same answer for y.
I usually pick the easierlooking equation.
after becoming a bit more proficient in your algebra, some of those last steps can be skipped.