a point (-3,2) lies on a circle whose equation is (x+3)squared +(y+1)squared=rsquared what is the radius of the circle plz put steps
come on, guy. Plug in the point:
(-3+3)^2 + (2+1)^2 = r^2
9 = r^2
I hope you can take it from there.
(-3+3)^2 + (2+1)^2 = r^2
9 = r^2
I hope you can take it from there.