Algebra
posted by Kyle on .
how would you solve these two equations.
ln x + ln(x+1)=1
ln(x+5) = ln(x1)  ln(x+1)

put to work the properties of logs.
ln x + ln(x+1) = 1
ln(x(x+1)) = 1
x(x+1) = e
x^2 + x  e = 0
then use the quadratic formula
ln(x+5) = ln(x1)/ln(x+1)
ln(x+5) = ln((x1)/(x+1))
x+5 = (x1)/(x+1)
x^2+6x+5 = x1
x^2+5x+6 = 0
...