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Calculus-concavity and graphing

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(2x+1)/(8x+1)
f is increasing for x:
f is decreasing for x:
find local max/min:

  • Calculus-concavity and graphing -

    y = (2x+1)/(8x+1)
    y' = -6/(8x+1)^2

    Since (8x+1)^2 is always positive, y' is never zero, so the are no mins or maxes.

    y is always decreasing. Check its graph to see how this can be.

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