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November 28, 2014

November 28, 2014

Posted by **Sara** on Wednesday, October 30, 2013 at 9:50pm.

f is increasing for x:

f is decreasing for x:

find local max/min:

- Calculus-concavity and graphing -
**Steve**, Thursday, October 31, 2013 at 5:18amy = (2x+1)/(8x+1)

y' = -6/(8x+1)^2

Since (8x+1)^2 is always positive, y' is never zero, so the are no mins or maxes.

y is always decreasing. Check its graph to see how this can be.

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