One more than 3 times a number is the same as 5 times the number, decreased by 15. Find the number.

• Assign the variable
• Write an equation
• Solve equation

1 + 3x = 5x - 15

1 + 3x-3x = 5x-3x - 15

1 = 2x - 15

1+15 = 2x - 15+15

16 = 2x

16/2 = 2x/2

8 = x or x = 8

3p+1 = 5p-15

3P+ 1+15 = 5P -15 +15
3p +16 = 5p
3p-3p+16 = 5p -3p

16 = 2p

p = 8

x = variable

3x + 1 = 5x - 15

16 = 2x

? = x

Well, well, well, let's solve this equation with a twist of humor! Shall we?

Let's call our mysterious number "x." So, one more than 3 times the number is simply (3x + 1). Now, onto the second part: 5 times the number, decreased by 15. That would be (5x - 15).

According to the problem, we want these two expressions to be equal, so:

3x + 1 = 5x - 15.

Now, let's do a little number dance and solve this equation!

Subtract 3x from both sides and add 15 to both sides:

15 + 1 = 5x - 3x.

Ta-da! We end up with:

16 = 2x.

Divide both sides by 2, and we discover our magical number:

x = 8.

So, the number we're looking for, my friend, is 8. I hope I've brought a smile to your face and helped you solve this equation in an amusing way!

To find the number, let's assign a variable to it. Let's call the number "x".

Now, let's write the equation based on the given information. It says "One more than 3 times a number is the same as 5 times the number, decreased by 15." We can represent this in equation form as:
3x + 1 = 5x - 15

To solve this equation, we need to isolate the variable (x) on one side of the equation. We can do this by performing inverse operations.

First, let's add 15 to both sides of the equation to get rid of the -15 on the right side:
3x + 1 + 15 = 5x - 15 + 15
3x + 16 = 5x

Next, let's subtract 3x from both sides of the equation to remove the 3x term from the left side:
3x - 3x + 16 = 5x - 3x
16 = 2x

Now, we can isolate x by dividing both sides of the equation by 2:
16/2 = 2x/2
8 = x

Therefore, the number is 8.