posted by HELP!!!! on .
A baseball player pops a pitch straight up. The ball (mass 230g ) was traveling horizontally at 36.0m/s just before contact with the bat, and 21.0m/s just after contact.
Determine the magnitude of the impulse delivered to the ball by the bat.
Determine the direction of the impulse delivered to the ball by the bat. Assume the initial direction of the ball as +x-axis direction.
Answer this Question
A. X = 36 m/s.
Y = 21 m/s.
V^2 = X^2 + Y^2 =
V^2 = 36^2 + 21^2 = 1737
V = 41.7 m/s.
Impulse = m*V = 0.23 * 41.7 = 9.59
B. tan A = Y/X = 21/36 = 0.58333
A = 30.3o = Direction.