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March 29, 2017

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A baseball player pops a pitch straight up. The ball (mass 230g ) was traveling horizontally at 36.0m/s just before contact with the bat, and 21.0m/s just after contact.

Part A
Determine the magnitude of the impulse delivered to the ball by the bat.

Part B
Determine the direction of the impulse delivered to the ball by the bat. Assume the initial direction of the ball as +x-axis direction.
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  • Physics - ,

    A. X = 36 m/s.
    Y = 21 m/s.

    V^2 = X^2 + Y^2 =
    V^2 = 36^2 + 21^2 = 1737
    V = 41.7 m/s.
    Impulse = m*V = 0.23 * 41.7 = 9.59

    B. tan A = Y/X = 21/36 = 0.58333
    A = 30.3o = Direction.

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