i have tried everything, please helpp
A snowmobile, with a mass of 530 kg, applied a force of 410 N backwards on the snow.
What force is responsible for the snowmobile’s resulting forward motion? (Hint: Think action–reaction force pairs.)
If the force of friction on the snowmobile is 187 N backwards, what is the net force acting on the snowmobile?
What is the acceleration of the snowmobile?
If the snowmobile accelerates for 7.3 s, what is its final speed?
How far would the snowmobile travel in this time?
The image above shows a person being “thrown” backwards as the snowmobile accelerates underneath him. Why would this happen?
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Well, well, well! It seems like you're in need of some help with your snowmobile physics problems. Don't worry, I'm here to clown around and give you some answers. Let's get started!
First of all, let's tackle the force responsible for the snowmobile's forward motion. According to Newton's Third Law, for every action, there is an equal and opposite reaction. So, the force responsible for the snowmobile's forward motion is actually the reaction force to the force applied by the snowmobile on the snow. In this case, the reaction force is also 410 N, but in the forward direction. So, it's a win-win situation for the snowmobile!
Now, let's talk about the net force acting on the snowmobile. It's like a math problem, but with a little twist. We have the force applied by the snowmobile (410 N backward) and the force of friction (187 N backward). To find the net force, we just need to subtract the force of friction from the force applied. So, mathematically it would be 410 N - 187 N = 223 N. Voila! That's the net force acting on the snowmobile.
Moving on to the acceleration of the snowmobile. Newton's Second Law comes into play here. It states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. So, using the formula F = ma, we can rearrange it to find the acceleration, which would be a = F/m. Plugging in the values (net force = 223 N, mass = 530 kg), we can find the acceleration. I'll let you do the math on this one!
Now, let's talk about the final speed of the snowmobile. To find the final speed, we can use the equation v = u + at, where v is the final speed, u is the initial speed (which we'll assume is 0), a is the acceleration (which you just calculated), and t is the time (which is given as 7.3 s). Plug in the values and you'll have your answer!
Lastly, let's address why the person is being "thrown" backwards as the snowmobile accelerates underneath him. It's all about that Newton's Third Law again! When the snowmobile accelerates in the forward direction, there is an equal and opposite reaction force acting on the person. This reaction force pushes the person backward, causing them to have a somewhat unexpected flight. So, you can say the person is having a "reverse joyride"!
I hope my clownish explanations have entertained you and helped you understand these physics concepts better. Good luck with your snowmobile adventures!
To answer your questions, let's go through step by step:
1. What force is responsible for the snowmobile's resulting forward motion? (Hint: Think action-reaction force pairs.)
According to Newton's third law of motion, every action has an equal and opposite reaction. Therefore, the force responsible for the snowmobile's resulting forward motion is the reaction force to the 410 N force applied by the snowmobile on the snow. So, the force responsible for the snowmobile's forward motion is also 410 N.
2. What is the net force acting on the snowmobile if the force of friction is 187 N backwards?
The net force is the vector sum of all the forces acting on an object. In this case, the force applied by the snowmobile (410 N) is in the opposite direction to the force of friction (187 N). To find the net force, we subtract the force of friction from the applied force:
Net Force = Force applied - Force of friction
Net Force = 410 N - 187 N = 223 N forward
3. What is the acceleration of the snowmobile?
To find the acceleration of the snowmobile, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:
Net Force = mass * acceleration
Using the net force calculated in the previous step (223 N) and the mass of the snowmobile (530 kg), we can rearrange the formula to solve for acceleration:
Acceleration = Net Force / Mass
Acceleration = 223 N / 530 kg ≈ 0.42 m/s²
4. If the snowmobile accelerates for 7.3 s, what is its final speed?
To find the final speed of the snowmobile, we can use the equation of motion:
Final Speed = Initial Speed + (Acceleration * Time)
Assuming the snowmobile starts from rest (initial speed is zero), we can substitute the values into the equation:
Final Speed = 0 + (0.42 m/s² * 7.3 s) ≈ 3.07 m/s
5. How far would the snowmobile travel in this time?
To find the distance traveled by the snowmobile, we can use the equation of motion as well:
Distance = Initial Speed * Time + (0.5 * Acceleration * Time^2)
Since the initial speed is zero, we can simplify the equation to:
Distance = 0.5 * Acceleration * Time^2
Substituting the given values:
Distance = 0.5 * 0.42 m/s² * (7.3 s)^2 ≈ 14.2 m
6. Why would the person be "thrown" backwards as the snowmobile accelerates underneath him?
According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In this case, the person and the snowmobile are experiencing the same acceleration, but because the person has a smaller mass compared to the snowmobile, they will experience a larger force relative to their mass. This results in the person being pushed backward as the snowmobile accelerates forward.
To answer these physics questions, we need to apply some key principles such as Newton's laws of motion. Let's go step-by-step:
1. What force is responsible for the snowmobile’s resulting forward motion?
According to Newton's third law of motion, every action has an equal and opposite reaction. In this case, the backward force applied by the snowmobile (410 N) creates an equal and opposite forward reaction force responsible for the snowmobile's motion. Therefore, the force responsible for the snowmobile's forward motion is also 410 N.
2. What is the net force acting on the snowmobile?
The net force is the vector sum of all forces acting on an object. In this case, we have a backward force by the snowmobile (410 N) and a backward force due to friction (187 N). To find the net force, we need to subtract the force due to friction from the force applied by the snowmobile: 410 N - 187 N = 223 N.
3. What is the acceleration of the snowmobile?
Newton's second law of motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Using the equation F = ma, where F is the net force (223 N) and m is the mass of the snowmobile (530 kg), we can solve for a: a = F/m. Plugging in the values, we get a = 223 N / 530 kg ≈ 0.42 m/s².
4. What is the final speed of the snowmobile after accelerating for 7.3 seconds?
To find the final speed, we can use the equation v = u + at, where v is the final speed, u is the initial speed (assumed to be 0 since the problem doesn't provide it), a is the acceleration (0.42 m/s²), and t is the time (7.3 s). Plugging in these values, we get v = 0 + (0.42 m/s²)(7.3 s) ≈ 3.07 m/s.
5. How far would the snowmobile travel in this time?
To find the distance traveled, we can use the equation x = ut + 0.5at², where x is the distance, u is the initial speed (again, assumed to be 0), a is the acceleration (0.42 m/s²), and t is the time (7.3 s). Plugging in these values, we get x = 0 + 0.5(0.42 m/s²)(7.3 s)² ≈ 1.04 m.
6. Why would a person be thrown backwards as the snowmobile accelerates?
This is due to Newton's third law of motion again. When the snowmobile applies a backward force to move forward, the person also experiences an equal and opposite reaction force pushing them backward. This is why the person appears to be thrown backward as the snowmobile accelerates.