Wednesday
March 29, 2017

Post a New Question

Posted by on .

Given that:
H2 (g) + F2 (g) ---> 2HF (g) H(rxn)= -546.6 kJ
2H2 (g) + O2 (g) ---> 2H2O (l) H (rxn)= -571.6 kJ

calculate the value for H(run) for...
2F2(g) + 2H2O (l) ---> 4HF (g) + O2 (g)

_____kJ?

  • Chemistry #27 - ,

    What's H(run) mean?

  • Chemistry #27 - ,

    Sorry i meant H(rxn) (of the reaction)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question