Monday
March 30, 2015

Homework Help: chemistry

Posted by robyn on Monday, October 28, 2013 at 8:14pm.

titration question:
How many moles of HCl must have been present in the 25mL of HCl solution in the 2 trials?

Given:
Trial 1: V of HCl= 25.00mL, V of NaOH used=29.50mL and M of NaOH=0.18M
Trial 2: V of HCl=25.00mL, V of NaOH used=28.50mL and M of NaOH=0.18M

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