Friday

April 18, 2014

April 18, 2014

Posted by **Terri** on Sunday, October 27, 2013 at 4:39pm.

Solve. Note in interval notation

So I got 19/6≤x

the other is suppose to be

x less than 7/3 but I can't get that

How do you get that

- Algebra -
**Steve**, Sunday, October 27, 2013 at 5:09pm5/(3x-7) <= 2

If 3x-7 > 0 (x > 7/3), then

5 <= 2(3x-7)

5/2 <= 3x-7

19/2 <= 3x

19/6 <= x

x >= 19/6

The original condition was x > 7/3, so x >= 19/6 works.

If 3x-7 < 0 (x < 7/3),

5 >= 2(3x-7)

19/6 >= x

x <= 19/6

The original condition was x < 7/3, but 7/3 < 19/6, so only the x < 7/3 part is a solution.

**Related Questions**

Algebra 2 - Solve. 4a-2≤a+1≤3a+4 4a-2-1≤a+1-1≤3a+4-1 4a-...

Solve Inequality - Solve the inequality. Express your solution using interval ...

Algebra - please check my answers. thanxs! Solve the polynomial inequality and ...

Math inequalitites - Hi, I need some help with some inequalitites. Thanks!! Use ...

Algebra - Solve and express in interval notation Solve: |5 – 8x| > 11 and ...

Algebra - Solve 3x +1 < 5 or 3x +1 > 4 By saying "solve," is it asking for...

Algebra 2 - Solve and write in interval notation: -3 ¡Ü (x − 4) / 2 < 4...

Math - Solve the compound inequality -1 < X - 2 LESS THAN OR EQUAL TO 7 Your ...

Inequality - please check my answers. thanxs! Solve the polynomial inequality ...

intermediate algebra - Hello, I am so stuck...I even watched two hours of videos...