Saturday

February 28, 2015

February 28, 2015

Posted by **Terri** on Sunday, October 27, 2013 at 4:39pm.

Solve. Note in interval notation

So I got 19/6≤x

the other is suppose to be

x less than 7/3 but I can't get that

How do you get that

- Algebra -
**Steve**, Sunday, October 27, 2013 at 5:09pm5/(3x-7) <= 2

If 3x-7 > 0 (x > 7/3), then

5 <= 2(3x-7)

5/2 <= 3x-7

19/2 <= 3x

19/6 <= x

x >= 19/6

The original condition was x > 7/3, so x >= 19/6 works.

If 3x-7 < 0 (x < 7/3),

5 >= 2(3x-7)

19/6 >= x

x <= 19/6

The original condition was x < 7/3, but 7/3 < 19/6, so only the x < 7/3 part is a solution.

**Answer this Question**

**Related Questions**

algebra 1 help please - 4) a student score is 83 and 91 on her first two quizzes...

Algebra 2 - Solve. 4a-2≤a+1≤3a+4 4a-2-1≤a+1-1≤3a+4-1 4a-...

Math inequalitites - Hi, I need some help with some inequalitites. Thanks!! Use ...

Math - Solve the compound inequality -1 < X - 2 LESS THAN OR EQUAL TO 7 Your ...

Pre Calculus - sec x = -2 , π ≤ x ≤ 3π Use a calculator to...

Math - Solve the inequality. Then graph the solution on a number line. -16 is ...

Math - Suppose cosA = 12/13 with 0º≤A≤90º. Suppose also that sinB = ...

Math - Suppose sinA = 12/13 with 90º≤A≤180º. Suppose also that sinB...

Math - Suppose sinA = 12/13 with 90º≤A≤180º. Suppose also that sinB...

Math - Suppose sinA = 12/13 with 90º≤A≤180º. Suppose also that sinB...