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December 18, 2014

December 18, 2014

Posted by **Anonymous** on Saturday, October 26, 2013 at 6:04pm.

The distance is increasing at

- calculas -
**Steve**, Saturday, October 26, 2013 at 10:37pmThe plane's x- and y- speed is

dx/dt = 19 cos 25°

dy/dt = 19 sin 25°

At time t, the distance z is

z^2 = x^2 + (y+4)^2

so,

2z dz/dt 2x dx/dt + 2(y+4) dy/dt.

Now just figure x,y,z at t=3, and plug in the values.

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