Posted by Sammy on .
Find the domain of:
6/(94x)
7/(x^28x)
(x^2+9x)/(x^313x^2+40x)

Algebra Help 
Kuai,
6/(94x)
94x =0
94x +4x = 0+4x
9= 4x
x =9/4
Domain of x is 9/4
7/(x^28x)
x^2 8x = 0
x(x8) =0
x =0
x 8 =0
x 8+8 = 0
x =8
domain of x are 0, 8
(x^2+9x)/(x^313x^2+40x))
x^313x^2+40x =0
x (x^213x +40) =0
x(x5)(x8) =0
x =0
x = 5
x = 8
Domain of x are 0, 5, and 8 
Algebra Help 
Steve,
the special values are correct, but the domain is all real numbers except those values.