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March 25, 2017

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Find the domain of:
6/(9-4x)
7/(x^2-8x)
(x^2+9x)/(x^3-13x^2+40x)

  • Algebra Help - ,

    6/(9-4x)

    9-4x =0
    9-4x +4x = 0+4x
    9= 4x
    x =9/4
    Domain of x is 9/4

    7/(x^2-8x)

    x^2 -8x = 0
    x(x-8) =0

    x =0
    x -8 =0
    x -8+8 = 0
    x =8

    domain of x are 0, 8


    (x^2+9x)/(x^3-13x^2+40x))

    x^3-13x^2+40x =0

    x (x^2-13x +40) =0

    x(x-5)(x-8) =0

    x =0
    x = 5
    x = 8

    Domain of x are 0, 5, and 8

  • Algebra Help - ,

    the special values are correct, but the domain is all real numbers except those values.

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