A solution is prepared by dissolving 5.00 g of ferric chloride in enough water to make 500.0 mL of stock solution. A 50.0 mL aliquot (portion) of this stock solution is then removed and added to 75.0 mL of water. Calculate the concentrations of all ions in the final solution.

I am going back to the original and pull them out one at a time. That way I can check against your answers instead of working all of them and you checking against mine. I would have done this first; however, my supper was on the table and I've been out of the shop for the last 2-3 hours.

To calculate the concentrations of all ions in the final solution, we need to follow these steps:

1. Calculate the molarity of the stock solution:
Molarity (M) is defined as moles of solute per liter of solution.
We know the mass of the solute (ferric chloride) is 5.00 g and the volume of the solution is 500.0 mL.
First, we need to convert the mass to moles using the molar mass of ferric chloride.
The molar mass of ferric chloride (FeCl3) can be calculated by adding the atomic masses of iron (Fe) and chlorine (Cl):
Molar mass of FeCl3 = (1 * atomic mass of Fe) + (3 * atomic mass of Cl)
Look up the atomic masses of Fe and Cl in the periodic table and calculate the molar mass.
Let's assume the molar mass of FeCl3 is X g/mol.

Now, we can calculate the number of moles of ferric chloride in the stock solution:
moles of ferric chloride = mass of ferric chloride / molar mass of ferric chloride
= 5.00 g / X g/mol

Next, we calculate the volume of the stock solution in liters:
volume of stock solution = 500.0 mL / 1000 mL/L

Finally, we can calculate the molarity of the stock solution:
Molarity of stock solution = moles of ferric chloride / volume of stock solution

2. Calculate the moles of ferric chloride in the aliquot:
The aliquot taken from the stock solution has a volume of 50.0 mL.

To calculate the moles of ferric chloride in this aliquot, we use the molarity and volume of the stock solution:
moles of ferric chloride in aliquot = Molarity of stock solution * volume of aliquot

3. Calculate the volume of the final solution:
The aliquot is added to 75.0 mL of water.
The total volume of the final solution is:
volume of final solution = volume of aliquot + volume of water

4. Calculate the concentration of ferric chloride ions in the final solution:
Concentration is defined as moles of solute per liter of solution.
We use the moles of ferric chloride in the aliquot and the volume of the final solution to calculate the concentration
Concentration of ferric chloride ions = moles of ferric chloride / volume of final solution

5. Calculate the concentration of chloride ions in the final solution:
Since ferric chloride fully dissociates in water, the number of moles of chloride ions is three times the moles of ferric chloride. So:
moles of chloride ions = 3 * moles of ferric chloride
Concentration of chloride ions = moles of chloride ions / volume of final solution

Now, let's fill in the given values and perform the calculations to find the concentrations of all ions in the final solution.