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Chemistry

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Using molar volume (STP) or the ideal gas law equation, determine the molar mass, g/mole, of each of the following:1.)11.1g of a gas that has a volume of 1.50L at STP. 2.) 0.742g of a gas that has a volume 860mL at 1.28atm and 18∘C. 3.) 2.42g of a gas that has a volume 1.88L at 695mmHg and 19∘C.

  • Chemistry - ,

    1)
    Use PV = nRT and solve for n = number of mols of the gas. Then n = grams/molar mass gas. You know grams and n, solve for molar mass.

    I think the others are done the same way.

  • Chemistry - ,

    How are we suppose to solve for the molar mass because we don't have the chemical formula for the gas?

  • Chemistry - ,

    Read my response again. I told you how.
    You use PV = nRT and solve for n = number of mols. Then n = grams/molar mass. You have n from the PV = nRT and you have grams from the problem. Substitute those and solve for molar mass of the gas. You're making it harder than it is. Don't get intimidated by chemistry.

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