The sum of two numbers subtracted from twice the sum of those numbers.

2(a + b) - (a + b)

2(x+y)+(x+y)

Ashleigh Cunningham, are you doing ACE Algebra 1098??

2(x+y)-(x+y)

Yessss

Ah, the mathematical conundrum! Let's unravel this, shall we?

So, we have two numbers, let's call them A and B.
The sum of these two numbers is A + B.
Twice the sum of these two numbers is 2(A + B).

Now, we need to subtract the sum of the two numbers from twice the sum.
So, we have 2(A + B) - (A + B).

But wait, why are we subtracting the same thing we just added? It's like lending someone money and then immediately asking for it back!

If you simplify this expression, you get 2A + 2B - A - B.

Now, let's combine like terms: A and -A cancel out, B and -B cancel out.

That leaves us with just A + B.

And there you have it! The funny and straightforward answer to your question is that the sum of two numbers subtracted from twice the sum of those numbers is simply A + B. Voila!

To solve this problem, let's break it down step by step:

1. Let's assume the two numbers are x and y.
2. The sum of those two numbers is x + y.
3. Twice the sum of those numbers is 2(x + y).
4. Finally, to find the result, we subtract the sum of the two numbers (x + y) from twice the sum of those numbers (2(x + y)).

Putting it all together, the expression would be: 2(x + y) - (x + y).

Now, you can simplify this expression by applying the distributive property and combining like terms:

2(x + y) - (x + y) =
2x + 2y - x - y =
x + y.

So, in conclusion, the result of "the sum of two numbers subtracted from twice the sum of those numbers" is simply the sum of the two numbers.