Iron reacts with chlorine to form iron(iii)chloride.

A)How many chlorines react with 1.86g of iron?
B)What mass of iron(iii)chloride is produced?

Write and balance the equation.

2Fe + 3Cl2 ==> 2FeCl3

Do you mean "How many mols Cl2 react with 1.86 g Fe?"
mols Fe = grams Fe/atomic mass Fe = approximately 0.03 but you need to be more accurate than that.

Using the coefficients in the balanced equation, convert mols Fe to mols Cl2.
That's 0.03 mols Fe x (3 mols Cl2/2 mol Fe) = approximately 0.03 x (3/2) = about 0.05 mols.

b.
Convert mols Fe to mols FeCl3. That's
about 0.03 x (2 mol FeCl3/2 mol Fe) = about 0.03 x 2/2 = about 0.03 mols FeCl3.
Convert that to grams. g = mols x molar mass.

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A) Well, iron is like the popular kid in chemistry class, always attracting attention. In this case, it reacts with chlorine to form iron(iii)chloride. Now, to figure out how many chlorines react with 1.86g of iron, we need to put on our thinking caps. Let's do some math!

The molar mass of iron is approximately 55.845 g/mol, and the molar mass of chlorine is approximately 35.453 g/mol. Since we're dealing with iron(iii)chloride, it means that one iron atom reacts with three chlorine atoms. That means we can calculate the number of chlorines in 1.86g of iron.

First, we need to convert 1.86g of iron to moles. So,
moles of iron = mass of iron / molar mass of iron
moles of iron = 1.86g / 55.845 g/mol

Once we have the number of moles of iron, we can find the number of moles of chlorine by multiplying it by the molar ratio between iron and chlorine. Since it's 1:3, we multiply the moles of iron by 3.

moles of chlorine = moles of iron * 3

Now, multiply the moles of chlorine by the molar mass of chlorine to get the mass of chlorine in grams.

mass of chlorine = moles of chlorine * molar mass of chlorine

And there you have it! The number of chlorines that react with 1.86g of iron.

B) Now, let's move on to the next question: "What mass of iron(iii)chloride is produced?" This is exciting, because we get to see the end result of the chemical reaction.

To find the mass of iron(iii)chloride, we need to know the molar mass of iron(iii)chloride. We can start by writing down the formula for iron(iii)chloride, which is FeCl3.

Using the molar masses of iron and chlorine that we mentioned earlier, we can calculate the molar mass of iron(iii)chloride by adding the molar masses of its constituent elements.

Now, we can use the molar mass of iron(iii)chloride to convert the moles of chlorine we calculated earlier to grams. We just need to multiply the moles of chlorine by the molar mass of iron(iii)chloride.

mass of iron(iii)chloride = moles of chlorine * molar mass of iron(iii)chloride

And voila! We have our answer. The mass of iron(iii)chloride produced. But remember, safety first!

To determine the number of chlorines that react with 1.86g of iron, we need to know the molar ratio between iron and chlorine in the reaction. The balanced chemical equation for the reaction between iron and chlorine is:

2 Fe + 3 Cl2 -> 2 FeCl3

From the equation, we can see that 2 moles of iron react with 3 moles of chlorine. Now, let's calculate the molar mass of iron (Fe) and chlorine (Cl).

The molar mass of iron (Fe) is approximately 55.85 g/mol.
The molar mass of chlorine (Cl) is approximately 35.45 g/mol.

A) To determine the number of chlorines that react with 1.86g of iron, we can set up a proportion using the molar ratio:

(1.86g Fe) / (55.85g/mol Fe) = (x) / (35.45g/mol Cl)

Solving for x, we find:

x = 1.86g Fe * (35.45g/mol Cl) / (55.85g/mol Fe)
x ≈ 1.18g Cl

Therefore, approximately 1.18g of chlorine reacts with 1.86g of iron.

B) To determine the mass of iron(III) chloride produced, we need to use the molar mass of iron(III) chloride (FeCl3), which is the sum of the molar masses of iron and three times the molar mass of chlorine:

Molar mass of FeCl3 = (55.85g/mol) + 3*(35.45g/mol)
Molar mass of FeCl3 ≈ 162.2 g/mol

Using the molar mass of FeCl3 and the molar ratio from the balanced chemical equation (2 Fe: 2 FeCl3), we can calculate the mass of iron(III) chloride produced:

(1.86g Fe) / (55.85g/mol Fe) * (162.2g/mol FeCl3) = (x) / (1mol FeCl3)

Simplifying the equation, we find:

x = 1.86g Fe * (162.2g/mol FeCl3) / (55.85g/mol Fe)
x ≈ 5.39g FeCl3

Therefore, approximately 5.39g of iron(III) chloride is produced.

To answer these questions, we need to use stoichiometry, which is a way of calculating the quantities of reactants and products in a chemical reaction.

1. To determine how many chlorines react with 1.86g of iron (Fe), we need to first write the balanced equation for the reaction:
2 Fe + 3 Cl2 -> 2 FeCl3

From the balanced equation, we can see that every 2 moles of iron react with 3 moles of chlorine.

Step 1: Calculate the molar mass of iron (Fe)
- The molar mass of iron is 55.85 g/mol.

Step 2: Convert the mass of iron (1.86g) to moles:
- Moles of Fe = mass of Fe / molar mass of Fe
- Moles of Fe = 1.86 g / 55.85 g/mol = 0.0333 mol (approximately)

Step 3: Apply the stoichiometry of the balanced equation:
- From the balanced equation, we know that 2 moles Fe react with 3 moles Cl2.
- Therefore, for every 2 moles of Fe, there are 3 moles of Cl2.
- Moles of Cl2 = (Moles of Fe) x (3 moles Cl2 / 2 moles Fe)
- Moles of Cl2 = 0.0333 mol x (3/2) = 0.0499 mol (approximately)

Step 4: Convert moles of Cl2 to mass:
- Mass of chlorine (Cl2) = Moles of Cl2 x Molar mass of Cl2
- Molar mass of Cl2 = 70.90 g/mol
- Mass of Cl2 = 0.0499 mol x 70.90 g/mol = 3.53 g (approximately)

So, 1.86g of iron reacts with approximately 3.53g of chlorine.

2. To determine the mass of iron(III) chloride (FeCl3) produced, we can utilize the same balanced equation:

Step 1: Calculate the molar mass of iron(III) chloride (FeCl3):
- The molar mass of FeCl3 is approximately 162.20 g/mol.

Step 2: Apply the stoichiometry of the balanced equation:
- 2 moles FeCl3 are produced for every 2 moles Fe that react.
- Since we found that 1.86g of Fe reacted, we can calculate the corresponding moles of FeCl3.
- Moles of FeCl3 = (Moles of Fe) x (2 moles FeCl3 / 2 moles Fe)
- Moles of FeCl3 = 0.0333 mol x 2 = 0.0666 mol (approximately)

Step 3: Convert moles of FeCl3 to mass:
- Mass of FeCl3 = Moles of FeCl3 x Molar mass of FeCl3
- Mass of FeCl3 = 0.0666 mol x 162.20 g/mol = 10.79 g (approximately)

Therefore, approximately 10.79g of iron(III) chloride is produced.