A disc has charge distribution sigma and radius R . What is the Electric Field in N/C at a point P , located a distance x directly above the center of the disc?Write your answer in terms of sigma, R ,x , k, and pi (type "pi"). Indicate multiplication with a "*" and division with a "/".

The charge between radii r and r + dr on the disk is:

sigma 2 pi r dr

The contribution to the potential from this charge is:

sigma/(4 pi epsilon) 2 pi r dr/sqrt(r^2 + x^2)

Integrating over r from 0 to R gives:

V(x) = sigma/(2 epsilon) [sqrt(R^2 + x^2) - x]

By symmetry, the electric field only has a component in the x-direction, this is minus the derivative of the potential w.r.t. x:

E(x) = sigma/(2 epsilon) [1 - x/sqrt(R^2 + x^2)]

To find the electric field at point P above the center of the disc, we can use Gauss's law. Gauss's law tells us that the electric field at a point above the center of a disc with charge distribution sigma is given by:

E = (sigma / (2 * epsilon0)) * (1 - (x / sqrt(x^2 + R^2)))

where epsilon0 is the electric constant, also known as the permittivity of free space.

In terms of sigma, R, x, k (Coulomb's constant), and pi, the equation becomes:

E = (sigma / (2 * k * pi)) * (1 - (x / sqrt(x^2 + R^2)))

Remember to substitute the value of k as k = 1 / (4 * pi * epsilon0) when calculating the electric field.

Therefore, the electric field at point P is given by:

E = (sigma / (2 * k * pi)) * (1 - (x / sqrt(x^2 + R^2)))

To find the electric field at a point P located a distance x directly above the center of the disc with charge distribution sigma and radius R, we can use the electric field formula for a charged disk.

The electric field formula for a charged disk at a point on the axis perpendicular to the disk's plane is given by:

E = (sigma / (2 * epsilon0)) * (1 - (x / sqrt(x^2 + R^2))),

where
- E is the electric field in N/C,
- sigma is the charge distribution on the disk in Coulombs per square meter (C/m^2),
- epsilon0 is the electric constant (~ 8.85 x 10^-12 C^2/(N * m^2)),
- x is the distance from the center of the disk to point P directly above it in meters, and
- R is the radius of the disk in meters.

However, in the formula above, we need to replace epsilon0 with the Coulomb constant, k, which is given by k = 1 / (4 * pi * epsilon0).

Therefore, the electric field, E, at point P is:

E = (sigma / (2 * k)) * (1 - (x / sqrt(x^2 + R^2))).

Note that the value of pi in this formula is simply "pi".