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December 18, 2014

December 18, 2014

Posted by **christina** on Sunday, October 20, 2013 at 11:35pm.

So it would be

Using the formula:

area = (1/2) ab sinŲ , where a and b are the sides and Ų is the contained angle

A = (1/2)(8*24)sinŲ

A = 96 sinŲ

dA/dt = 96cosŲ dŲ/dt

given: dŲ/dt = .05

dA /dt = 96(cos(135)(.05) = -3.40

I keep getting it wrong?

- math -
**Reiny**, Sunday, October 20, 2013 at 11:53pmWho says it is wrong?

I get the same result

Make a sketch with the arms at 135° ........ (90+45)

if you increase the angle , you will see that the area is actually getting smaller, (the lines eventually will become a straight line, at which point the area is zero)

at Ų = 134.99° , A = 67.894097

at Ų = 135.01° , A = 67.87040..

notice that the area has decreased slightly for that small increase in the angle

- math -
**christina**, Sunday, October 20, 2013 at 11:57pmMy online homework says it is wrong. I tried it without the negative sign too

- math -
**Anonymous**, Monday, October 21, 2013 at 12:26am-4.78

- math -
**Kuai**, Monday, October 21, 2013 at 12:30amdA /dt = 96(cos(135)(.05) = -3.39

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