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November 26, 2014

November 26, 2014

Posted by **christina** on Sunday, October 20, 2013 at 10:53pm.

- math -
**Reiny**, Sunday, October 20, 2013 at 11:13pmUsing the formula:

area = (1/2) ab sinŲ , where a and b are the sides and Ų is the contained angle

A = (1/2)(15(18)sinŲ

A = 135 sinŲ

dA/dt = 135 cosŲ dŲ/dt

given: dŲ/dt = -.08 , and cos 120° = -.5

dA /dt = 135(-.5)(-.08) = 5.4 m^2

when the angle is 120°, the area is increasing at 5.4 m^2/s

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