on a farm, there are some cows and some chickens. if the animals have a total of 40 heads and 112 legs, how many cows are there?

since each animal only has one head, there must have been 40 animals

let the number of cows be x
then the number of chickes is 40-x

4x + 2(40-x) = 112
4x + 80 - 2x = 112
2x = 32
x = 16

so 16 cows and 24 chickens

THANKS!!!!

How did u get 2 ??!

ima **** you *** to hell you dummy

in a farm there are some cows and some chickens.If the animals have a total number of 35 heads and 96 legs, how many cows and chickens are there

On a farm, there are some cows and some chickens.

If there are a total of 16 heads and 44 feet, then
How many cows and chickens are there?

plsplspls help i'm pretty stressed out right now. it's due today.

Farmer Joe has cows and chickens on his farm. His farm animals have 96 legs and 36 heads total. How many cows and how many chickens are on the farm?

To find the number of cows on the farm, we can use a system of equations based on the number of heads and legs.

Let's denote the number of cows as 'C' and the number of chickens as 'h' (note that the question does not specify the number of chickens).

Each cow has one head and four legs, so the total number of cow heads and legs can be expressed as:
Cows' heads = C
Cows' legs = 4C

Each chicken has one head and two legs, so the total number of chicken heads and legs can be expressed as:
Chickens' heads = h
Chickens' legs = 2h

Based on the information given in the question, we know that the total number of heads is 40 and the total number of legs is 112. Using these equations, we can set up a system of equations:

C + h = 40 (equation 1)
4C + 2h = 112 (equation 2)

To solve this system, we can use either substitution or elimination method. In this case, let's use the elimination method. Multiply equation 1 by 2 to make the coefficients of 'h' in both equations equal:

2C + 2h = 80 (equation 3)
4C + 2h = 112 (equation 2)

Next, subtract equation 3 from equation 2, eliminating the 'h' term:

(4C + 2h) - (2C + 2h) = 112 - 80
2C = 32

Divide both sides by 2 to solve for C:

C = 32 / 2
C = 16

Therefore, there are 16 cows on the farm.

The answer is 8 million

X=cow

Y=chicken
X+y=35
Y=35-X
4x+2(35-x) =96
4x+70-2x=96
4x-2x=96-70
2x=26
X=26:2
X=13(cows)
Chicken=35-13
=22 chickens