Divide: -39x^4 by underroot13 multiplied by x^2 and please explain it.
Steve already answered you
http://www.jiskha.com/display.cgi?id=1382172829
Solve? I don't see an equals sign.
Why don't you do it, we will check it. Why would you want someone to reduce this for you?
To divide -39x^4 by √13 multiplied by x^2, follow these steps:
Step 1: Simplify the expression.
First, divide -39x^4 by x^2:
-39x^4 / x^2 = -39x^(4-2) = -39x^2
Step 2: Simplify the expression further.
Next, divide -39x^2 by √13:
-39x^2 / √13 = (-39x^2 * 1) / √13
To divide by a square root, you need to multiply both the numerator and denominator by the conjugate of the denominator (√13).
The conjugate of √13 is -√13.
Multiply the numerator and denominator by -√13:
((-39x^2 * 1) / √13) * (-√13 / -√13) = (-39x^2 * -√13) / (-√13 * √13) = (39x^2 * √13) / (13)
Simplifying further, we have:
(39x^2 * √13) / 13
So, -39x^4 divided by √13 multiplied by x^2 simplifies to:
(39x^2 * √13) / 13