Posted by Anonymous on .
A 28.9 g sample of ethylene glycol, a car radiator coolant, loses 689 J of heat. What was the initial temperature of ethylene glycol if the final temperature is 32.5°C (c of ethylene glycol = 2.42 J/gK)?
q = 689 = mass coolant x specific heat x (Tfinal-Tinitial)
The only unknown is Ti