what is the probability of 2 tall pea plants hetrozygous for the tall allele producing a short pea plant
If short is recessive, 25%. If short is dominant, 75%.
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the answer is 25%
To calculate the probability of 2 tall pea plants heterozygous for the tall allele (Tt) producing a short pea plant, we need to use the principles of Mendelian genetics. It's important to note that in this scenario, the allele for tallness (T) is dominant over the allele for shortness (t).
First, let's establish the genotype of the plants involved:
- The tall pea plants are heterozygous, which means they carry both the dominant and recessive alleles for height (Tt).
- The short pea plant would have to be homozygous recessive (tt) to exhibit the short phenotype.
To determine the probability, we can use a Punnett square. A Punnett square is a visual representation that shows the possible combinations of alleles from the parents.
Since both of the tall pea plants are heterozygous (Tt), we can create a Punnett square like this:
T t
------------------
T | TT Tt
------------------
T | TT Tt
The four boxes in the Punnett square represent the potential offspring genotypes. From the Punnett square, we can see that there is a 25% chance (1 box out of 4) for the plants to produce a short pea plant with the genotype "tt."
Therefore, the probability of 2 tall pea plants heterozygous for the tall allele producing a short pea plant is 25%.