Posted by **Tracy** on Thursday, October 17, 2013 at 9:23pm.

y=3/4x-1 write equation for a line parallel to the given line passing through (4,0)

- Algebra parallel and perpendicular -
**Kuai**, Thursday, October 17, 2013 at 9:38pm
y = mx +b

0 = -3/4(4) + b

0 = -3 + b

b = 3

y = -3/4x + 3

- Algebra parallel and perpendicular -
**Tracy**, Thursday, October 17, 2013 at 9:57pm
Thank you. can you explain the steps that you used.

- Correction - Algebra parallel and perpendicular -
**Reiny**, Thursday, October 17, 2013 at 11:41pm
Kuai is not correct, his line is NOT parallel with the given, since the slopes are different

easiest way:

if the new line is parallel to the given one, it must differ only in the constant

so new equation is

y = (3/4)x + b

sub in (4.0)

0 = (3/4)(4) + b

b = -3

y = (3/4)x - 3

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