Algebra parallel and perpendicular
posted by Tracy on .
y=3/4x1 write equation for a line parallel to the given line passing through (4,0)

y = mx +b
0 = 3/4(4) + b
0 = 3 + b
b = 3
y = 3/4x + 3 
Thank you. can you explain the steps that you used.

Kuai is not correct, his line is NOT parallel with the given, since the slopes are different
easiest way:
if the new line is parallel to the given one, it must differ only in the constant
so new equation is
y = (3/4)x + b
sub in (4.0)
0 = (3/4)(4) + b
b = 3
y = (3/4)x  3