y=3/4x-1 write equation for a line parallel to the given line passing through (4,0)

y = mx +b

0 = -3/4(4) + b
0 = -3 + b
b = 3
y = -3/4x + 3

Thank you. can you explain the steps that you used.

Kuai is not correct, his line is NOT parallel with the given, since the slopes are different

easiest way:
if the new line is parallel to the given one, it must differ only in the constant

so new equation is
y = (3/4)x + b
sub in (4.0)
0 = (3/4)(4) + b
b = -3

y = (3/4)x - 3

To write the equation for a line parallel to the given line and passing through the point (4,0), we can use the fact that parallel lines have the same slope.

The given equation is y = (3/4)x - 1, and we can see that the slope of this line is 3/4.

So, the slope of the line parallel to this will also be 3/4.

Now we can use the point-slope form of a linear equation to write the equation for the parallel line. The point-slope form is given by:
y - y1 = m(x - x1)

Where m is the slope and (x1, y1) is a point on the line.

Plugging in the values, in this case, m = 3/4 and (x1, y1) = (4,0), we get:

y - 0 = (3/4)(x - 4)

Simplifying, we have:

y = (3/4)x - 3

Therefore, the equation for the line parallel to the given line passing through (4,0) is y = (3/4)x - 3.