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Algebra parallel and perpendicular

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y=3/4x-1 write equation for a line parallel to the given line passing through (4,0)

  • Algebra parallel and perpendicular - ,

    y = mx +b
    0 = -3/4(4) + b
    0 = -3 + b
    b = 3
    y = -3/4x + 3

  • Algebra parallel and perpendicular - ,

    Thank you. can you explain the steps that you used.

  • Correction - Algebra parallel and perpendicular - ,

    Kuai is not correct, his line is NOT parallel with the given, since the slopes are different

    easiest way:
    if the new line is parallel to the given one, it must differ only in the constant

    so new equation is
    y = (3/4)x + b
    sub in (4.0)
    0 = (3/4)(4) + b
    b = -3

    y = (3/4)x - 3

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